SOLUTION: Let f(x) be sqrt(3-x) where x <= 1, x^2 where 1<x<3 and 27/x where x >= 3. Find: limit of f(x) as x approaches 1- limit of f(x) as x approaches 1+ limit of f(x) as x approache

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Let f(x) be sqrt(3-x) where x <= 1, x^2 where 1<x<3 and 27/x where x >= 3. Find: limit of f(x) as x approaches 1- limit of f(x) as x approaches 1+ limit of f(x) as x approache      Log On


   

Question 1027652: Let f(x) be sqrt(3-x) where x <= 1, x^2 where 1= 3.
Find:
limit of f(x) as x approaches 1-
limit of f(x) as x approaches 1+
limit of f(x) as x approaches 1
limit of f(x) as x approaches 3-
limit of f(x) as x approaches 3+
limit of f(x) as x approaches 3
limit of f(x) as x approaches 9
limit of f(x) as x approaches -6
Where is f discontinuous?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The diagram helps to answer the questions.
.
.
.
.
.
.
.
lim%28x-%3E1L%2Cf%28x%29%29=sqrt%282%29
lim%28x-%3E1R%2Cf%28x%29%29=1
lim%28x-%3E1%2Cf%28x%29%29=DNE<--- Does not exist
lim%28x-%3E3L%2Cf%28x%29%29=9
lim%28x-%3E3R%2Cf%28x%29%29=9
lim%28x-%3E3%2Cf%28x%29%29=9
lim%28x-%3E9%2Cf%28x%29%29=3
lim%28x-%3E-6%2Cf%28x%29%29=3%29
.
.
.
Discontinuous at x=1 since lim%28x-%3E1L%2Cf%28x%29%29%3C%3Elim%28x-%3E1R%2Cf%28x%29%29