SOLUTION: How many liters of a 40% acid solution should be mixed with 8 liters of a 25% acid solution to obtain a solution that is 30% acid? State what x represents, state the equation, and

Algebra ->  Average -> SOLUTION: How many liters of a 40% acid solution should be mixed with 8 liters of a 25% acid solution to obtain a solution that is 30% acid? State what x represents, state the equation, and      Log On


   

Question 1027600: How many liters of a 40% acid solution should be mixed with 8 liters of a 25% acid solution to obtain a solution that is 30% acid? State what x represents, state the equation, and then state the answer.
Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
How many liters of a 40% acid solution should be mixed with 8 liters of a 25% acid solution
to obtain a solution that is 30% acid? State what x represents, state the equation, and then state the answer.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

Let x be the required amount (volume) of a 40% acid solution.

Then the equation for the pure acid volume is 

0.4x + 0.25*8 = 0.3*(x + 8).

Simplify and solve:

0.4x + 2 = 0.3x + 2.4,

0.4x - 0.3x = 2.4 - 2,

0.1x = 0.4,

x = 0.4%2F0.1 = 4.

Answer. 4 liters of 40% acid solution is needed.