SOLUTION: Please help with the following problem: Solve the system by addition method: Eq 1 states 3x + 3y = 33 Eq 2 states 5x - 2y = 27 Please show work. Thank you

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Question 102756This question is from textbook
: Please help with the following problem:
Solve the system by addition method:
Eq 1 states 3x + 3y = 33
Eq 2 states 5x - 2y = 27
Please show work.
Thank you
This question is from textbook

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

3%2Ax%2B3%2Ay=33
5%2Ax-2%2Ay=27

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 3 and 5 to some equal number, we could try to get them to the LCM.

Since the LCM of 3 and 5 is 15, we need to multiply both sides of the top equation by 5 and multiply both sides of the bottom equation by -3 like this:

5%2A%283%2Ax%2B3%2Ay%29=%2833%29%2A5 Multiply the top equation (both sides) by 5
-3%2A%285%2Ax-2%2Ay%29=%2827%29%2A-3 Multiply the bottom equation (both sides) by -3


So after multiplying we get this:
15%2Ax%2B15%2Ay=165
-15%2Ax%2B6%2Ay=-81

Notice how 15 and -15 add to zero (ie 15%2B-15=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%2815%2Ax-15%2Ax%29%2B%2815%2Ay%2B6%2Ay%29=165-81

%2815-15%29%2Ax%2B%2815%2B6%29y=165-81

cross%2815%2B-15%29%2Ax%2B%2815%2B6%29%2Ay=165-81 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

21%2Ay=84

y=84%2F21 Divide both sides by 21 to solve for y



y=4 Reduce


Now plug this answer into the top equation 3%2Ax%2B3%2Ay=33 to solve for x

3%2Ax%2B3%284%29=33 Plug in y=4


3%2Ax%2B12=33 Multiply



3%2Ax=33-12 Subtract 12 from both sides

3%2Ax=21 Combine the terms on the right side

cross%28%281%2F3%29%283%29%29%2Ax=%2821%29%281%2F3%29 Multiply both sides by 1%2F3. This will cancel out 3 on the left side.


x=7 Multiply the terms on the right side


So our answer is

x=7, y=4

which also looks like

(7, 4)

Notice if we graph the equations (if you need help with graphing, check out this solver)

3%2Ax%2B3%2Ay=33
5%2Ax-2%2Ay=27

we get



graph of 3%2Ax%2B3%2Ay=33 (red) 5%2Ax-2%2Ay=27 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (7,4). This verifies our answer.