SOLUTION: Manuel can drive 3 times faster then Carlos can ride his bike. if it takes Carlos 2 hours longer than Manuel to travel 21 miles, how fast can Carlos ride his bike? 21 21 __

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Question 1027487: Manuel can drive 3 times faster then Carlos can ride his bike. if it takes Carlos 2 hours longer than Manuel to travel 21 miles, how fast can Carlos ride his bike?
21 21
__ - __ = 2 ??
5x x
Need help setting this problem up.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
21/(5x)-21/x=2

Put between triple left braces and triple right braces,
21%2F%285x%29-21%2Fx=2

Simplest common denominator is 5x.
Multiply the left member and the right member by 5x.

5x%2821%2F%285x%29-21%2Fx%29=5x%282%29

Simplify! Continue on to solve.

Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!
Manuel can drive 3 times faster then Carlos can ride his bike. if it takes Carlos 2 hours longer than Manuel to travel 21 miles, how fast can Carlos ride his bike?
21 21
__ - __ = 2 ??
5x x
Need help setting this problem up.
I have no idea what kind of equation you set up here!

3 TIMES FASTER is actually 4 times Carlos' speed but it's the norm, in today's math questions setup, that
3 TIMES FASTER means 3 TIMES AS FAST. Ridiculous!!
Let Carlos’ speed be S
Assuming this to actually mean, 3 TIMES AS FAST, we get Manuel’s speed as: 3S, and the following TIME equation: 21%2FS+=+21%2F%283S%29+%2B+2
63 = 21 + 6S -------- Multiplying by LCD, 3S
63 – 21 = 6S
42 = 6S
S, or Carlos’ speed = 42%2F6, or highlight_green%28matrix%281%2C2%2C+7%2C+mph%29%29
I just realized I went too far and should've stopped at: 21%2FS+=+21%2F3S+%2B+2