SOLUTION: Twice the sum of Jerry and David's age is equivalent to ten years less than three times Frank's age. David is 9 years younger than Jerry and Frank is 5 years older than Jerry. Writ

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Question 1027476: Twice the sum of Jerry and David's age is equivalent to ten years less than three times Frank's age. David is 9 years younger than Jerry and Frank is 5 years older than Jerry. Write and solve an algebraic equation to find the age of all three men.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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J=Jerry's age; D=David's age=J-9; F=Frank's age=J+5
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2(J+D)=3F-10
2(J+(J-9))=3(J+5)-10
2(2J-9)=3J+15-10
4J-18=3J+5
J=23
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D=J-9=23-9=14
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F=J+5=23+5=28
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ANSWER: Jerry is 23, David is 14, and Frank is 28.
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CHECK:
2(J+D)=3F-10
2(23+14)=3(28)-10
2(37)=84-10
74=74
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