SOLUTION: Identify the axis of symmetry, create a suitable table of values, then sketch the graph (including the axis of symmetry). Could someone help me please?
{{{y=x^2-5x+4}}}
Algebra ->
Graphs
-> SOLUTION: Identify the axis of symmetry, create a suitable table of values, then sketch the graph (including the axis of symmetry). Could someone help me please?
{{{y=x^2-5x+4}}}
Log On
Question 102742: Identify the axis of symmetry, create a suitable table of values, then sketch the graph (including the axis of symmetry). Could someone help me please? Answer by jim_thompson5910(35256) (Show Source):
So the x-coordinate of the vertex is (which is in decimal form). Lets plug this into the equation to find the y-coordinate of the vertex.
Lets evaluate
Start with the given polynomial
Plug in
Raise 2.5 to the second power to get 6.25
Multiply 5 by 2.5 to get 12.5
Now combine like terms
So the vertex is (2.5,-2.25)
Since the x-coordinate is 2.5, this means the axis of symmetry is
Now lets find 2 other points to the left of the vertex
Lets evaluate
Start with the given polynomial
Plug in
Raise 0 to the second power to get 0
Multiply 5 by 0 to get 0
Remove any zero terms
So our 1st point is (0,4)
----Now lets find another point----
Lets evaluate
Start with the given polynomial
Plug in
Raise 1 to the second power to get 1
Multiply 5 by 1 to get 5
Now combine like terms
So our 2nd point is (1,0)
Now remember, the parabola is symmetrical about the axis of symmetry (which is )
This means the y-value for is equal to the y-value of . So when , .
Also, the y-value for is equal to the y-value of . So when , .
Now lets make a table of the values we have calculated
x
y
0
4
1
0
2.5
-2.25
4
0
5
4
Notice if you graph the equation with the axis of symmetry you get
Graph of through the given points. Notice the axis of symmetry is the equation which is the vertical line through the vertex of the parabola.