SOLUTION: The nickels and dimes fell on the floor. There were 12 more nickels than dimes, and the total value was $5.10. How many nickels and how man dimes were on the floor?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: The nickels and dimes fell on the floor. There were 12 more nickels than dimes, and the total value was $5.10. How many nickels and how man dimes were on the floor?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1027332: The nickels and dimes fell on the floor. There were 12 more nickels than dimes, and the total value was $5.10. How many nickels and how man dimes were on the floor?

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x=dimes
x+12=nickels
.10x+.05(x+12)=5.10
.10x+.05x+.60=5.10
.15x=4.50
x=30 dimes ($3.00)
x+12=42 nickels ($2.10)
total is $5.10
Answer is 30 dimes and 42 nickels