SOLUTION: Factor completely: b^3m^3-14b^2m^2+49bm Here are my options, which do not help me at all:( a) bm9b^2m^2-14bm+49) b) bm(bm-7)(bm+7) c) m(b^3m-7b^2) d) bm(bm-7)^2 Plea

Algebra ->  Expressions-with-variables -> SOLUTION: Factor completely: b^3m^3-14b^2m^2+49bm Here are my options, which do not help me at all:( a) bm9b^2m^2-14bm+49) b) bm(bm-7)(bm+7) c) m(b^3m-7b^2) d) bm(bm-7)^2 Plea      Log On


   

Question 102704: Factor completely:
b^3m^3-14b^2m^2+49bm
Here are my options, which do not help me at all:(
a) bm9b^2m^2-14bm+49)
b) bm(bm-7)(bm+7)
c) m(b^3m-7b^2)
d) bm(bm-7)^2
Please help me understand this a little better. Thank you, thank you.
Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
b%5E3m%5E3-14b%5E2m%5E2%2B49bm
First you will factor out any commons, they each have bm, so we will factor that out;
bm%28b%5E2-14b%2B49%29
Now factor the equation;
bm(bm-7)(bm-7)
bm%28bm-7%29%5E2
Hope this helps
:)