Question 1026941: If a fair coin is tossed 5 times, what is the probability that the coin will land face up at least twice?
I attempted this problem many times and always ended up with a large sheet of paper with many scribbles on it. I think that there are 32 total possible outcomes but I'm not sure how to calculate the probability of "at least" questions?
*sorry for the double submission, i entered the wrong email*
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! At least 2 means "2, 3, 4, and 5".
So find the probability of each and add the probabilities up.
You could also find the probability of 0 and 1, add them, and subtract by 1.
That may be the easiest way.
You're correct, there are 32 possible outcomes.
One of them is no heads.
TTTTT
So the probability of 0 heads is,
For one head, there are five possible outcomes,
HTTTT THTTT TTHTT TTTHT TTTTH
So there are 5 possible outcomes and then,
So then the added probability is,
We're looking for the complement so,
|
|
|
