Question 1026821: n=3; 2 and 4i are zeros; f (-1)= -102
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! n=3; 2 and 4i are zeros; f (-1)= -102
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If you want a polynomial with Real Number coefficients, -4i is also a zero.
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f(x) = a(x-2)(x-4i)(x+4i)
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f(x) = a(x-2)(x^2+16)
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Use f(-1) = -102 to find "a"::
f(-1) = a(-3)(1+16) = -102
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-51a = -102
a = 2
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Ans: f(x) = 2(x-2)(x^2+16)
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Cheers,
Stan H.
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