You can put this solution on YOUR website! Find the equation of the normal line to the curve y = 3x^3 + 4x^2 - 5x + 1 at x = 1. Thank youuuu
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slope = 9x^2 + 8x - 5
f'(1) = 9 + 8 - 5 = 12
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slope of normal:: -1/12
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f(1) = 3 + 4 - 5 + 1 = 3
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Find linear equation with m = -1/12 passing thru (1,3)
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Form::
3 = (-1/12)1 + b
b = (37/12)
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Equation::
y = (-1/12)x + (37/12)
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Cheers,
Stan H.
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