SOLUTION: An experiment consists of rolling two fair dice and adding the dots on the two sides facing up.assuming each simple event is as likely as any other, find the probability that th

Algebra ->  Probability-and-statistics -> SOLUTION: An experiment consists of rolling two fair dice and adding the dots on the two sides facing up.assuming each simple event is as likely as any other, find the probability that th      Log On


   

Question 1026621: An experiment consists of rolling two fair dice and adding the dots
on the two sides facing up.assuming each simple event is as likely
as any other, find the probability that the sum of the dots is not
2, 4, or 6.
Answer by Edwin McCravy(20065) About Me  (Show Source):
You can put this solution on YOUR website!
From these 36 possible rolls:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) 

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) 

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) 

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  

we remove all the ones that have sum 2, 4, or 6 

      (1,2)       (1,4)       (1,6)

(2,1)       (2,3)       (2,5) (2,6) 

      (3,2)       (3,4) (3,5) (3,6) 

(4,1)       (4,3) (4,4) (4,5) (4,6) 

      (5,2) (5,3) (5,4) (5,5) (5,6) 

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

I count that there are 27 remaining that
do not have sum 2, 4, or 6.

The probability is 27 out of 36 or 27/36
which reduces to 3/4.

Edwin