Question 1026572: Please help!!!
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
(tan θ − 3)(9 sin^2 θ − 1) = 0
Answer by FrankM(1040)   (Show Source):
You can put this solution on YOUR website! (tan θ − 3)(9 sin^2 θ − 1) = 0
When we have A * B = 0, the roots are A=0, B=0 so we start with
Tan θ - 3 = 0
Tan θ = 3
θ = 71.565 degrees +/- 180N (tangen has a 180 period
(9 sin^2 θ − 1) = 0
This factors to
(3 sin θ − 1)(3 sin θ + 1) = 0 and
3 sin θ − 1 = 0
3 sin θ = 1
sin θ = 1/3
θ = 19.4712 degrees, and 160.5288 degrees (+/-360N on both answers)
3 sin θ + 1 = 0
3 sin θ = -1
sin θ = -1/3
θ = -19.4712 degrees, and -160.5288 degrees (+/-360N on both answers)
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