SOLUTION: solve the following equation for theta, 0<theta<360, rounded to the nereast tenth of a degree.
2cos theta=5+6/cos theta
1.{27.6°}
2.{27.6°, 332.4°}
3.{152.4°, 207.6°}
4.
Algebra ->
Trigonometry-basics
-> SOLUTION: solve the following equation for theta, 0<theta<360, rounded to the nereast tenth of a degree.
2cos theta=5+6/cos theta
1.{27.6°}
2.{27.6°, 332.4°}
3.{152.4°, 207.6°}
4.
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You can put this solution on YOUR website! solve the following equation for theta,
2cos theta=5+6/cos theta
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2*cos(t) = 5 + 6/cos(t)
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2cos^2(t = 5cos(t) + 6
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2cos^2(t) - 5*cos(t) - 6 = 0
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cos(t) = [5 +- sqrt(25-4*2*-6)]/4
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cos(t) = [5 +- sqrt(73)]/4
Comment:: Both cos(t) value are extraneous
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Cheers,
Stan H.
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t = invcos(-1.18
1.{27.6°}
2.{27.6°, 332.4°}
3.{152.4°, 207.6°}
4. 2 and 3
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