| 
 
 
| Question 1026491:  Smith was traveling X miles to Boston at M miles per hour and arrived 2 hours late for the party. How fast should he have traveled to have arrived on time? ---
 I got xm/x/m-2, which I know is wrong. An explanation of how to do this problem correctly would be greatly appreciated. Thanks!
 
 Answer by Boreal(15235)
      (Show Source): 
You can put this solution on YOUR website! The distance is x miles the speed is M mph
 the time it took is miles/miles per hour, and that is x/M
 The speed he needed was two hours less than that, or (x/M)-2, or (x-2M)/M.  Those units are mph
 The distance is unchanged, and its units are miles.
 The speed needed is xM/(x-2M).ANSWER
 Try an example.
 480 miles, and he drove at 60 mph, taking 8 hours.  He needed to get there in 6 hours, so he needed to drive 80 mph.
 Use the speed he went, 60 mph
 480*60/(480-120)=480*60/360
 This is (1/6)*480=80 mph
 
 | 
  
 | 
 |