SOLUTION: If 108 attend a concert and tickets for adults cost $3.5 while tickets for children cost $2.75 and total receipts for the concert was $351.75, how many of each went to the concert?
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-> SOLUTION: If 108 attend a concert and tickets for adults cost $3.5 while tickets for children cost $2.75 and total receipts for the concert was $351.75, how many of each went to the concert?
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Question 1026490: If 108 attend a concert and tickets for adults cost $3.5 while tickets for children cost $2.75 and total receipts for the concert was $351.75, how many of each went to the concert? Answer by Edwin McCravy(20059) (Show Source):
Let the number of adults' tickets be x
Let the number of children's tickets be y
Money Money
Type Number from from
of of EACH ALL
ticket tickets ticket tickets
-------------------------------------------
adult's x $3.50 $3.50x
children's y $2.75 $2.75y
-------------------------------------------
TOTALS 108 ----- $351.75
The first equation comes from the second column.
x + y = 108
The second equation comes from the last column.
3.50x + 2.75y = 351.75
Get rid of decimals by multiplying every term by 100:
350x + 275y = 35175
So we have the system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 108
y = 108 - x
Substitute (108 - x) for y in 350x + 275y = 35175
350x + 275(108 - x) = 35175
350x + 29700 - 275x = 35175
75x + 29700 = 35175
75x = 5475
x = 73 = the number of adult tickets.
Substitute in y = 108 - x
y = 108 - (73)
y = 35 children's tickets.
Checking: 73 adults' is $255.50 and 35 children's is $96.25
That's 108 tickets.
And indeed $255.50 + $96.25 = $351.75
Edwin