SOLUTION: Please help me solve these problems: 1. Given f(x)=2x^2 - 6, then, to the nearest hundredth, the positive x-value that gives the smallest value of y=sqrt(f(x)) is? 2. The y

Algebra ->  Test -> SOLUTION: Please help me solve these problems: 1. Given f(x)=2x^2 - 6, then, to the nearest hundredth, the positive x-value that gives the smallest value of y=sqrt(f(x)) is? 2. The y      Log On


   

Question 1026406: Please help me solve these problems:
1. Given f(x)=2x^2 - 6, then, to the nearest hundredth, the positive x-value that gives the smallest value of y=sqrt(f(x)) is?
2. The y-coordinate of the "endpoint" of the graph of y=4sqrt(2-x)+3 is
Thank you in advance, your help is always appreciated.
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
1. y+=+sqrt%28f%28x%29%29+=+sqrt%282x%5E2-6%29 would have the domain 2x%5E2+-+6+%3E=0, or (-infinity, -sqrt%283%29]∪[sqrt%283%29, infinity). Incidentally the smallest value of y happens when x = -sqrt%283%29 or x = sqrt%283%29. So the answer to your question is sqrt%283%29, approximately 1.73 to nearest hundredth.
2. The "endpoint" of the graph of y=4sqrt%282-x%29%2B3 happens when x = 2, which is the minimum point of the graph. The corresponding y-value is y = 3.