SOLUTION: I need help with this problem, Santo paid $16.25 to buy 5 children tickets and 1 adult ticket. Hulda paid $24.00 to buy 4 children tickets and 3 adult tickets. If both people paid

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: I need help with this problem, Santo paid $16.25 to buy 5 children tickets and 1 adult ticket. Hulda paid $24.00 to buy 4 children tickets and 3 adult tickets. If both people paid       Log On


   



Question 1026404: I need help with this problem, Santo paid $16.25 to buy 5 children tickets and 1 adult ticket. Hulda paid $24.00 to buy 4 children tickets and 3 adult tickets. If both people paid the same price per ticket, what was the price of an adult ticket?
Answer by ikleyn(53751) About Me  (Show Source):
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I need help with this problem, Santo paid $16.25 to buy 5 children tickets and 1 adult ticket.
Hulda paid $24.00 to buy 4 children tickets and 3 adult tickets.
If both people paid the same price per ticket, what was the price of an adult ticket?
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5*c + 1*a = 1625,     (1)      (Santo paid)
4*c + 3*a = 2400.     (2)      (Hulda paid)

where "c" is for children ticket price and "a" is for the adult ticket price.

Now, from (1) express a = 1625 - 5c, and substitute it into (2). You will get

4c + 3*(1625 -5c) = 2400.

Simplify and solve for c:

4c + 4875 - 15c = 2400,

-11c = 2400 - 4875,

-11c = -2475,

c = %28%28-2475%29%2F%28-11%29%29 = 225.

So the children ticket is 225 cents = $2.25.

The adult ticket is (from (1)) a = 1625 - 5*c = 1625 - 5*225 = 500 cents = $5.