SOLUTION: Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696.00 more than th
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-> SOLUTION: Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696.00 more than th
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Question 1026343: Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696.00 more than they need to pay. What was the price for the computer? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696.00 more than they need to pay. What was the price for the computer?
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Equations:
s = (5/6)f
f = (7/8)c
f + s = c + 696
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Substitute for f and for s ; solve for "c"::
(7/8)c + (5/6)(7/8)c + c = 696
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[1 + (5/6)](7/8)c + c = 696
(11/6)(7/8)c = 696
(77/48)c = 696
computer = 48*696/77 = $433.87
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Cheers,
Stan H.
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