SOLUTION: Dalton, the tinsmith, has two pieces of sheet metal with the same area. one is a square and the other is a rectangle 18cm longer than the square, but the width is 9cm less than the
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Dalton, the tinsmith, has two pieces of sheet metal with the same area. one is a square and the other is a rectangle 18cm longer than the square, but the width is 9cm less than the
Log On
Question 1026326: Dalton, the tinsmith, has two pieces of sheet metal with the same area. one is a square and the other is a rectangle 18cm longer than the square, but the width is 9cm less than the square. Find the total area of each piece of metal. Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
If you make the length and
width of the square = x
Length of rectangle = x + 18
Width of rectangle = x - 9
Area of square = Area of rectangle
x * x = (x + 18)(x - 9) (* times)
x^2 = x^2 + 9x - 162
x^2 - x^2 = 9x - 162
0 = 9x - 162
9x = 162
x = 18
Area of square = 18^2 = 324 cm^2
Area of rectangle = (18 + 18)(18 - 9)
= (36) * (9)
= 324 cm^2
Hope this helps :-)
