SOLUTION: A Box contains 10 red and 12 white rose flowers. flowers are picked up at random one by one without replacement. What is probability that
(i) The first 3 flowers are red?
(ii) Th
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-> SOLUTION: A Box contains 10 red and 12 white rose flowers. flowers are picked up at random one by one without replacement. What is probability that
(i) The first 3 flowers are red?
(ii) Th
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Question 1026293: A Box contains 10 red and 12 white rose flowers. flowers are picked up at random one by one without replacement. What is probability that
(i) The first 3 flowers are red?
(ii) There are 2 red and 2 white flowers in the first four picked up?
(iii) The third one is red given that the first 2 are white?
You can put this solution on YOUR website! a. (10/22)(9/21)(8/20)=0.0779 (30/385)
b. The denominator is 22*21*20*19
The numerator is 6 ways this can happen, which will contain the number 10*9*12*11
two red then two white would be 10/22 * 9/21 *12/20*11/19.
The numerator is 71280
The denominator is 175560. The probability is 0.4060
c.When the first two are white, there are 20 flowers left. The probability that the third flower is red is 10/20 or 1/2.
