SOLUTION: Count the number of horizontal and vertical asymptotes of f(x)= 2x^2-5x-1÷4x^2-1

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Question 1026206: Count the number of horizontal and vertical asymptotes of f(x)= 2x^2-5x-1÷4x^2-1
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Vertical asymptotes : Find where the denominator equals zero.
4x%5E2-1=0
4x%5E2=1
x%5E2=1%2F4
There are 2 of them (x=1%2F2) and (x=-1%2F2).
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Horizontal asymptotes : Look at the limit of the quotient as x goes to infinity and -infinity

There is 1 horizontal asymptote (y=1%2F2).
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