SOLUTION: Jim travels 5 mph less than 2 times as fast as Brenda. Starting at the same point and traveling in the same direction, they are 292.5 miles apart after 7.5 hours. Find their spee

Algebra ->  Expressions-with-variables -> SOLUTION: Jim travels 5 mph less than 2 times as fast as Brenda. Starting at the same point and traveling in the same direction, they are 292.5 miles apart after 7.5 hours. Find their spee      Log On


   



Question 1026093: Jim travels 5 mph less than 2 times as fast as Brenda. Starting at the same point and traveling in the same direction, they are 292.5 miles apart after 7.5 hours. Find their speeds
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = the distance in miles Brenda travels
after 7.5 hrs
+d+%2B+292.5+ = the distance in miles Jim travels
after 7.5 hrs
Let +s+ = Brenda's speed in mi/hr
+2s+-+5+ = Jim's speed in mi/hr
------------------------------
Brenda's equation:
(1) +d+=+s%2A7.5+
Jim's equation:
(2) +d+%2B+292.5+=+%28+2s+-+5+%29%2A7.5+
------------------------------
Substitute (1) into (2)
(2) +s%2A7.5+%2B+292.5+=+%28+2s+-+5+%29%2A7.5+
(2) +7.5s+%2B+292.5+=+15s+-+37.5+
(2) +7.5s+=+292.5+%2B+37.5+
(2) +7.5s+=+330+
(2) +s+=+44+
and
+2s+-+5+=+2%2A44+-+5+
+2s+-+5+=+83+
Brenda's speed is 44 mi/hr
Jim's speed is 83 mi/hr
-------------------
check:
(1) +d+=+s%2A7.5+
(1) +d+=+44%2A7.5+
(1) +d+=+330+
and
(2) +d+%2B+292.5+=+%28+2s+-+5+%29%2A7.5+
(2) +d+%2B+292.5+=+%28+2%2A44+-+5+%29%2A7.5+
(2) +d+=+83%2A7.5+-+292.5+
(2) +d+=+622.5+-+292.5+
(2) +d+=+330+
OK