SOLUTION: A furniture shop refinishes tables. Employees use one of two methods to refinish each table. Method I takes 2 hours and the material costs $8. Method II takes 2.5 hours, and the

Algebra ->  Expressions-with-variables -> SOLUTION: A furniture shop refinishes tables. Employees use one of two methods to refinish each table. Method I takes 2 hours and the material costs $8. Method II takes 2.5 hours, and the      Log On


   



Question 1026091: A furniture shop refinishes tables. Employees use one of two methods to refinish each table. Method I takes 2 hours and the material costs $8. Method II takes 2.5 hours, and the material costs $6. Next week, they plan to spend 333 hours in labor and $940 in material for refinishing tables. How many tables should they plan to refinish with each method
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Let m and n represent method I and method II, respectively. Then:
2m+2.5n=333
8m+6n=940
Then:
8m+10n=1332
4n=392
n=98
m=44
They can refinish 44 tables using method I, and 98 using method II. ☺☺☺☺