SOLUTION: There are estimates of the margin of error for confidence levels other than 95%. For a 90% confidence level and a sample size of n, the margin of error is approximately
82/ sq ro
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82/ sq ro
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Question 1026086: There are estimates of the margin of error for confidence levels other than 95%. For a 90% confidence level and a sample size of n, the margin of error is approximately
82/ sq root of n %
%.
Suppose we wish to have a margin of error of 2% with a 90% confidence level. Approximately how many people should we interview?
You can put this solution on YOUR website! Suppose we wish to have a margin of error of 2% with a 90% confidence level. Approximately how many people should we interview?
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n = [1.645/0.02]^2*(1/2)^2 = 1691 when rounded up
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Cheers,
Stan H.
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