SOLUTION: The bases of two parallelograms are the same length height of the first parallelogram is half the height of the second what is the ratio of the area of the first parallelogram to t

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Question 1026028: The bases of two parallelograms are the same length height of the first parallelogram is half the height of the second what is the ratio of the area of the first parallelogram to the area of the second justify your answer
Answer by Theo(13342) About Me  (Show Source):
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area of a parallelogram is b * h, where:

b = the length of the base.
h = the length of the height.

since the bases are the same length, we'll use b for the base of each.l

since the height of the first parallelogram is equal to 1/2 * the height of the second parallelogram, we'll use h for the height of the first parallelogram and we'll use 2h for the height of the second parallelogram.

the area of the first parallelogram is equal to b * h.

the area of the second parallelogram is equal to b * 2 * h.

the ratio of the area of the first parallelogram to the area of the second parallelogram is equal to (b * h) / (b * 2 * h)

the b and the h in the numerator and the denominator cancel out and the result is that the ratio of the area of the first parallelogram to the area of the second parallelogram is 1/2.