Question 102586: given the x-intercepts of y=x^2-4x-21
a. (-3,0)and (7,0)
b. (3,0) and (-4,0)
c. (-7,0) and (4,0)
d. No x-intercepts
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! To find the x-intercepts, you have to let y=0 and solve for x
Let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve ( notice , , and )
Plug in a=1, b=-4, and c=-21
Negate -4 to get 4
Square -4 to get 16 (note: remember when you square -4, you must square the negative as well. This is because .)
Multiply to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
or
Lets look at the first part:
Add the terms in the numerator
Divide
So one answer is
Now lets look at the second part:
Subtract the terms in the numerator
Divide
So another answer is
So our solutions are:
or
Notice when we graph , we get:
and we can see that the roots are and . This verifies our answer
This means the x-intercepts are (-3,0) and (7,0). So the answer is A
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