SOLUTION: How wide should a parabolic satellite dish be at its opening if the receiver (focus) is placed 6 feet away from the vertex and it is 12 feet deep at its center?
Algebra ->
Quadratic-relations-and-conic-sections
-> SOLUTION: How wide should a parabolic satellite dish be at its opening if the receiver (focus) is placed 6 feet away from the vertex and it is 12 feet deep at its center?
Log On
Question 1025783: How wide should a parabolic satellite dish be at its opening if the receiver (focus) is placed 6 feet away from the vertex and it is 12 feet deep at its center? Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! Imagine parabola with vertex at the origin on a coordinate system, and focus is (0,6). The directrix is the line (x,-6). You can derive the equation of the parabola according to the definition of a parabola and using the Distance Formula.
(