SOLUTION: to do a work independently B requires six days more than what A requires. if they work together ,it will take two days less than what A alone takes.in how many days can B alone com
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-> SOLUTION: to do a work independently B requires six days more than what A requires. if they work together ,it will take two days less than what A alone takes.in how many days can B alone com
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Question 102576: to do a work independently B requires six days more than what A requires. if they work together ,it will take two days less than what A alone takes.in how many days can B alone complete the work? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! The equation is:
(A's rate alone) + (B's rate alone) = (A & B rates working together)
or, in other words
(1 job / A's time) + (1 job / B's time) = 1 job / time working together
Let A = A's time to complete job alone
Let B = B's time to complete job alone
The problem says B = A + 6
and time working together = A - 2
multiply both sides by
Subtract from both sides and are the solutions, but you can
discard the negative one
So, A gets the job done in 6 days working alone
B took six days more than A working alone
or, B takes 12 days working alone
To verify,
A = 6
B = 12 is this true? yes, it's true
