Question 1025577: what equation passes through (10,10) & is perpendicular to the line described by y=-1/2x-3? Found 3 solutions by stanbon, mananth, KMST:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! what equation passes through (10,10) & is perpendicular to the line described by y=-1/2x-3?
slope of given line:: -1/2
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slope of perpendicular line:: 2
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Form of answer line:: y = mx + b
Solve for "m" and for "b"::
10 = 2*10 + b
b = -10
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Ans: y = 2x-10
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Cheers,
Stan H.
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You can put this solution on YOUR website! Equation of a perpendicular line
y = - 1/ 2 x -3
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = - 1/2
The slope of a line perpendicular to the above line will be the negative reciprocal 2
Because m1*m2 =-1
The slope of the required line will be 2
m= 2 ,point ( 10 , 10 )
Find b by plugging the values of m & the point in
y=mx+b
10 = 20 + b
b= -10
m= 2
The required equation is y = 2 x -10
m.ananth@hotmail.ca
You can put this solution on YOUR website! The slope of a line with equation is ,
so the slope of a line with equation is ,
so for a line perpendicular to slope of a line with equation , ---> .
A line with slope passing through point
has the equation (in point-slope form),
so the line passing through (10,10) and perpendicular to the line described by
has the equation <--->
(