SOLUTION: Three consecutive integers are such that three times the smallest is 18 more than the largest. Find The Integers

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Question 1025566: Three consecutive integers are such that three times the smallest is 18 more than the largest. Find The Integers
Answer by macston(5194) About Me  (Show Source):
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S=smallest integer; M=middle integer=S+1; L=largest integer=S+2
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3S=L+18
3S=(S+2)+18
3S=S+20
2S=20
S=10
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M=S+1=10+1=11
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L=S+2=10+2=12
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ANSWER: The integers are 10, 11, and 12.
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CHECK:
3S=L+18
3(10)=12+18
30=30
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