SOLUTION: A metallurgist has one alloy containing 21% titanium and another containing 63% titanium. How many pounds of each alloy must he use to make 42 pounds of a third alloy containing 22
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Question 1025506: A metallurgist has one alloy containing 21% titanium and another containing 63% titanium. How many pounds of each alloy must he use to make 42 pounds of a third alloy containing 22% titanium? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A metallurgist has one alloy containing 21% titanium and another containing 63% titanium.
How many pounds of each alloy must he use to make 42 pounds of a third alloy containing 22% titanium?
:
let x = the 63% alloy amt
then
(42-x) = 21% alloy
:
A typical mixture equation
.63x + .21(42-x) = .22(42)
.63x + 8.82 - .21x = 9.24
.63x - .21x = 9.24 - 8.82
.42x = .42
x = .42/.42
x = 1 lb of 63% alloy
then
42 - 1 = 41 lb of 21% alloy
:
:
You can check this for yourself in the original mixture equation
.63(1) + .21(41) = .22(42)
