Question 102548: Find two consecutive positive integers such that the sum of
their squares is 85.
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Consecutive integers follow the form: , , , ...., etc.
Which means their squares are , , etc
So the sum of their squares is:
Foil
Subtract 85 from both sides
Let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve ( notice , , and )
Plug in a=2, b=2, and c=-84
Square 2 to get 4
Multiply to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 2 to get 4
So now the expression breaks down into two parts
or
Lets look at the first part:
Add the terms in the numerator
Divide
So one answer is
Now lets look at the second part:
Subtract the terms in the numerator
Divide
So another answer is
So our solutions are:
or
So that means our first number is either 6 or -7. If the first number is 6, then the second number is 7
Check:
Since the two squares add to 85, our answer is verified.
If the first number is -7, then the second number is -6
Check:
Since the two squares add to 85, our answer is verified.
So our two numbers could be
6 and 7
or
-7 and -6
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