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| Question 102548:  Find two consecutive positive integers such that the sum of
 their squares is 85.
 
 Answer by jim_thompson5910(35256)
      (Show Source): 
You can put this solution on YOUR website! Consecutive integers follow the form:  ,  ,  , ...., etc. 
 
 Which means their squares are
  ,  , etc 
 So the sum of their squares is:
 
 
   
 
 
  Foil 
 
 
  Subtract 85 from both sides 
 Let's use the quadratic formula to solve for x:
 
 
 Starting with the general quadratic
 
 
   
 the general solution using the quadratic equation is:
 
 
   
 
 
 So lets solve
  ( notice  ,  , and  ) 
 
 
 
 
  Plug in a=2, b=2, and c=-84 
 
 
 
  Square 2 to get 4 
 
 
 
  Multiply  to get   
 
 
 
  Combine like terms in the radicand (everything under the square root) 
 
 
 
  Simplify the square root (note: If you need help with simplifying the square root, check out this  solver) 
 
 
 
  Multiply 2 and 2 to get 4 
 So now the expression breaks down into two parts
 
 
  or   
 Lets look at the first part:
 
 
   
 
  Add the terms in the numerator 
  Divide 
 So one answer is
 
   
 
 
 Now lets look at the second part:
 
 
   
 
  Subtract the terms in the numerator 
  Divide 
 So another answer is
 
   
 So our solutions are:
 
  or   
 
 So that means our first number is either 6 or -7. If the first number is 6, then the second number is 7
 
 
 Check:
 
 
  Since the two squares add to 85, our answer is verified. 
 If the first number is -7, then the second number is -6
 
 
 Check:
 
 
  Since the two squares add to 85, our answer is verified. 
 
 
 So our two numbers could be
 6 and 7
 
 or
 
 -7 and -6
 
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