SOLUTION: hi I need some help please the problem states to solve 4 log( 2x + 1 ) = 12. I think I understand how it simplifies to 8 log (x) + 4 log (-12) = 0 , but I'm not sure if that is the
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Exponential-and-logarithmic-functions
-> SOLUTION: hi I need some help please the problem states to solve 4 log( 2x + 1 ) = 12. I think I understand how it simplifies to 8 log (x) + 4 log (-12) = 0 , but I'm not sure if that is the
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Question 1025478: hi I need some help please the problem states to solve 4 log( 2x + 1 ) = 12. I think I understand how it simplifies to 8 log (x) + 4 log (-12) = 0 , but I'm not sure if that is the correct answer or not. Thank you for your help. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 8 log (x) + 4 log (-12) = 0
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log(-12) is not allowed, no negative argument.
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4 log( 2x + 1 ) = 12
Divide by 4
log(2x+1) = 3
log(2x+1) = log(10^3) = log(1000)
2x+1 = 1000
2x = 999
x = 999/2
