Question 1025472: How many liters of a 60% acid solution must be mixed with 20% acid solution to get 320 liters of a 50% acid solution? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! How many liters of a 60% acid solution must be mixed with 20% acid solution to get 320 liters of a 50% acid solution?
------------
Do it like this:
How many liters of a 65% acid solution must be mixed with 10% acid solution to get 320 liters of a 30% acid solution?
---------------
s = amount of 65%
t = amount of 10%
---
s + t = 320 (total solution)
65s + 10t = 320*30 (total acid)
==========
s + t = 320 --> t = 320 - s
65s + 10t = 320*30 = 9600
Sub for t
65s + 10(320-s) = 9600
75s + 3200 = 9600
s = 6400/75
s = 256/3 liters
t = 704/3 liters
