SOLUTION: Separate 102 into two parts such that the larger part divided by the smaller part gives a quotient of 6 and a remainder of 11.

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Question 1025270: Separate 102 into two parts such that the larger part divided by the smaller part gives a quotient of 6 and a remainder of 11.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
A%2BB=102
,
,
,
B%2FA=6%2B11%2FA
B=6A%2B11
,
,
,
Substitute,
A%2B%286A%2B11%29=102
7A=91
A=13
Then,
B=6%2813%29%2B11
B=89