SOLUTION: Graph the inequality. 3x + y_<_5 Of course the line is a solid line under the < If someone could help me with this problem AND how to write the < with a line u

Algebra ->  Trigonometry-basics -> SOLUTION: Graph the inequality. 3x + y_<_5 Of course the line is a solid line under the < If someone could help me with this problem AND how to write the < with a line u      Log On


   



Question 102518: Graph the inequality.
3x + y_<_5

Of course the line is a solid line under the < If someone could help me with this problem AND how to write the < with a line under it I would appreciate it.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Simply surround the expression 3x+y<=5 with 3 curly braces, they look like this: { and }, to get 3x%2By%3C=5. If you're not sure, just click the link "show source"


In order to graph 3x%2By%3C=5, we need to graph the equation 3x%2By=5 (just replace the inequality sign with an equal sign).
So lets graph the line 3x%2By=5 (note: if you need help with graphing, check out this solver)
+graph%28+500%2C+500%2C+-20%2C+20%2C+-20%2C+20%2C+-3x%2B5%29+ graph of 3x%2By=5
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality 3x%2By%3C=5 with the test point

Substitute (0,0) into the inequality
3%280%29%2B%280%29%3C=5 Plug in x=0 and y=0
0%3C=5 Simplify



(note: for some reason, some of the following images do not display correctly in Internet Explorer. So I would recommend the use of
Firefox to see these images.)


Since this inequality is true, we simply shade the entire region that contains (0,0)
Graph of 3x%2By%3C=5 with the boundary (which is the line 3x%2By=5 in red) and the shaded region (in green)