SOLUTION: If Cesar has 17 nickels and quarters in his pocket, and they have a combined value of 265 cents, how many of each coin does he have ?
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Question 1025173: If Cesar has 17 nickels and quarters in his pocket, and they have a combined value of 265 cents, how many of each coin does he have ? Answer by Edwin McCravy(20060) (Show Source):
Let the number of nickels be x
Let the number of quarters be y
Value Value
Type Number of of
of of EACH ALL
coin coins coin coins
-------------------------------------------
nickels x $0.05 $0.05x
quarters y $0.25 $0.25y
-------------------------------------------
TOTALS 17 ----- $2.65
The first equation comes from the second column.
x + y = 17
The second equation comes from the last column.
0.05x + 0.25y = 2.65
Get rid of decimals by multiplying every term by 100:
5x + 25y = 265
So we have the system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 17
y = 17 - x
Substitute (17 - x) for y in 5x + 25y = 265
5x + 25(17 - x) = 265
5x + 425 - 25x = 265
-20x + 425 = 265
-20x = -160
x = 8 = the number of nickels.
Substitute in y = 17 - x
y = 17 - (8
y = 9 quarters.
Checking: 8 nickels is $0.40 and 9 quarters is $2.25
That's 17 coins.
And indeed $0.40 + $2.25 = $2.65
Edwin