Question 1025171: The height, h, in feet of a golf ball above the ground after being hit into the air is given by the equation, h = -16t^2 + 64t, where t is the number of seconds elapsed since the ball was hit. How many seconds does it take for the golf ball to hit the ground?
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! The height, h, in feet of a golf ball above the ground after being hit into the air is given by the equation, h = -16t^2 + 64t, where t is the number of seconds elapsed since the ball was hit. How many seconds does it take for the golf ball to hit the ground?
-------
h = -16t^2 + 64t
It hits the ground when h=0.
-16t^2 + 64t = 0
Solve for t
|
|
|
