SOLUTION: Question Right Here> http://s1042.photobucket.com/user/marcus0809/media/all_zps9otfdub0.png.html?filters[user]=144860371&filters[recent]=1&sort=1&o=0 Help is very appreciated.

Algebra ->  Parallelograms -> SOLUTION: Question Right Here> http://s1042.photobucket.com/user/marcus0809/media/all_zps9otfdub0.png.html?filters[user]=144860371&filters[recent]=1&sort=1&o=0 Help is very appreciated.       Log On


   

Question 1025149: Question Right Here>
http://s1042.photobucket.com/user/marcus0809/media/all_zps9otfdub0.png.html?filters[user]=144860371&filters[recent]=1&sort=1&o=0
Help is very appreciated.
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
The diagonals of a parallelogram bisect each other, then
:
PT = TR
QT = TS
:
we are given
:
y = 2x + 1
4y = 6x + 10
:
we have two equations in two unknowns
:
substitute for y in second equation
:
4(2x+1) = 6x + 10
:
8x+4 = 6x + 10
:
2x = 6
:
*********
x = 3
y = 7
********
:
check the answers by substituting in second equation
:
4*7 = 6*3 + 10
:
28 = 28
our answer checks