SOLUTION: Car X and car Y traveled the same 80km route. If car X took 2 hours and car Y traveled at an average speed that was 50% faster than the average speed of car X, how long did it tak

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Question 1025061: Car X and car Y traveled the same 80km route. If car X took 2 hours and car Y traveled at an average speed that was 50% faster than the average speed of car X, how long did it take car Y to travel the route?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +t+ = time in hrs for car Y
Let +s+ = speed in km/hr for car X
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Equation for car X:
(1) +80+=+s%2A2+
Equation for car Y:
(2) +80+=+1.5s%2At+
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(1) +s+=+80%2F2+
(1) +s+=+40+ km/hr
Plug this result into (2)
(2) +80+=+1.5s%2At+
(2) +80+=+1.5%2A40%2At+
(2) +80+=+60t+
(2) +t+=+4%2F3+
(2) +t+=+1+%2B+1%2F3+ hrs
+%281%2F3%29%2A60+=+20+
Car Y's time is 1 hr and 20 min
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check:
(2) +80+=+1.5s%2At+
(2) +80+=+1.5s%2A%284%2F3%29+
(2) +3%2A80+=+1.5%2A4%2As+
(2) +240+=+6s+
(2) +s+=+40+ km/hr
OK