SOLUTION: Taxi a charges 4.50 plus .18 per mile driven. Taxi b charges 5.10 plus .12 per mile driven. When would taxi a cost less? When would taxi b cost less? When would they cost the same
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-> SOLUTION: Taxi a charges 4.50 plus .18 per mile driven. Taxi b charges 5.10 plus .12 per mile driven. When would taxi a cost less? When would taxi b cost less? When would they cost the same
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Question 1025026: Taxi a charges 4.50 plus .18 per mile driven. Taxi b charges 5.10 plus .12 per mile driven. When would taxi a cost less? When would taxi b cost less? When would they cost the same and how much.
Cost = 4.5 + .18x
Cost = 5.10 + .12x
I can't figure out the equation to solve the problem Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39630) (Show Source):
You can put this solution on YOUR website! The equations look good. Graphing each would make the answers more visual and understandable.
Doing instead all through symbols, you can rename the cost function of each taxi.
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When (or for what x miles) would taxi b cost less? (Inequality for this; not equation)
---------------Number of miles becomes greater than 10.
You can put this solution on YOUR website! Taxi a charges 4.50 plus .18 per mile driven. Taxi b charges 5.10 plus .12 per mile driven. When would taxi a cost less? When would taxi b cost less? When would they cost the same and how much.
Cost = 4.5 + .18x
Cost = 5.10 + .12x
I can't figure out the equation to solve the problem
Except for the the last question, you don't create equations, but inequalities instead
"a" < "b"
With D being the distance, we get: 4.5 + .18D < 5.1 + .12D
.18D - .12D < 5.1 - 4.5
.06D < .6
D, or distance that'd make "a" cost less than "b" is: , or
D, or distance that'd make "b" cost less than "a" is: , or
D, or distance that'd make the 2 cost the same is: , or
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