SOLUTION: Find average rate of change over interval [15,16], given f(x)=log(base2)x+1 i was given the formula F(b)-F(a)/b-a and i did [(log(base2)(16)+1)-log(base2)(15)+1)]/[16-15] now sh

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Find average rate of change over interval [15,16], given f(x)=log(base2)x+1 i was given the formula F(b)-F(a)/b-a and i did [(log(base2)(16)+1)-log(base2)(15)+1)]/[16-15] now sh      Log On


   



Question 1024917: Find average rate of change over interval [15,16], given f(x)=log(base2)x+1
i was given the formula F(b)-F(a)/b-a
and i did [(log(base2)(16)+1)-log(base2)(15)+1)]/[16-15]
now should i do (4+1)-(3.9+1) which will equal 0.1?Thank you for your time in advance

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find average rate of change over interval [15,16], given f(x)=log(base2)x+1
i was given the formula F(b)-F(a)/b-a
and i did [(log(base2)(16)+1)-log(base2)(15)+1)]/[16-15]
now should i do (4+1)-(3.9+1) which will equal 0.1?Thank you for your time in advance
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If you mean
f%28x%29=log%282%2Cx%29%2B1 (it appears so):
--> %284+%2B+1%29+-+%28log%282%2C15%29+%2B+1%29
=~ 5 - (3.9+1)
=~ 0.1