SOLUTION: I need some help with this problem: Differentiate: y = {{{lnx^2}}} + 1 + {{{e^(2x)/ (sec x + 1)}}}

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Question 1024913: I need some help with this problem:
Differentiate: y = lnx%5E2 + 1 + e%5E%282x%29%2F+%28sec+x+%2B+1%29
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let's do it in sections.
y%5B1%5D=ln%28x%5E2%29
dy%2Fdx=%281%2Fx%5E2%29%282x%29=2%2Fx
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y%5B2%5D=1
dy%2Fdx=0
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y%5B3%5D=e%5E%282x%29%2F%28sec%28x%29%2B1%29%29



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Putting it all together,