SOLUTION: When a number is added to twice another number the sum is 37. If the two numbers differ by 2, what are the two numbers?

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Question 1024871: When a number is added to twice another number the sum is 37. If the two numbers differ by 2, what are the two numbers?
Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
X+2Y=37
Y-2=X
(Y-2)+2Y=37
3Y=39
Y=13
X=11
11+26=37 and 11 and 13 differ by 2.