SOLUTION: (2/3 p to the power of 4 y cubic) ( y to the power of 4 s to the power of 5) ( 6 p squared s cube)

Algebra ->  Exponents -> SOLUTION: (2/3 p to the power of 4 y cubic) ( y to the power of 4 s to the power of 5) ( 6 p squared s cube)      Log On


   

Question 1024759: (2/3 p to the power of 4 y cubic) ( y to the power of 4 s to the power of 5) ( 6 p squared s cube)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
(2/3 p to the power of 4 y cubic) ( y to the power of 4 s to the power of 5) ( 6 p squared s cube)
:
%28%282%2F3%29p%5E4y%5E3%29%28y%5E4s%5E5%29%286p%5E2s%5E3%29
we don't need the brackets
%282%2F3%29p%5E4y%5E3y%5E4s%5E5%2A6p%5E2s%5E3
group like terms
%282%2F3%29p%5E4%2A6p%5E2%2Ay%5E3%2Ay%5E4%2As%5E5%2As%5E3
2/3 of 6 is 4, add the exponents of like terms so we have
4p%5E6%2Ay%5E7%2As%5E8