Question 1024750: John made two investments totaling $25,000. On one investment he made a 12% profit. On the other, he took a 19% loss. He made a net loss of $1,030. How much was in each investment?
Found 2 solutions by Theo, MathTherapy:
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! x = amount of investment that made a 12% profit.
y = amount of investment that made a 19% loss.
you have 2 equations.
x + y = 25000
.12x - .19y = 1030
solve for y in the first equation to get y = 25000 - x.
replace y with that in the second equation to get .12x - .19 * (25000 - x) = 1030.
solve for x in the second equation to get x = 18645.16129.
since y = 25000 - x, you get y = 6354.83871.
john invested 18645.16129 that earned 12% profit.
his profit was .12 * 18645.16129 = 2237.419355.
john invested 6354.83871 that earned him 19% loss.
his loss was .19 * 6354.83871 = 1207.419355.
his net profit was 2237.419355 - 1207.419355 = 1030.
Answer by MathTherapy(10557)  (Show Source):
You can put this solution on YOUR website!
John made two investments totaling $25,000. On one investment he made a 12% profit. On the other, he took a 19% loss. He made a net loss of $1,030. How much was in each investment?
Amount invested that yielded a 12% profit: 
Amount invested that yielded a 19% loss: $25,000 - $12,000 = 
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