SOLUTION: Ten times the smallest of three consecutive integers is twenty-two mire than three times the sum of the integers

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Question 1024615: Ten times the smallest of three consecutive integers is twenty-two mire than three times the sum of the integers
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Ten times the smallest of three consecutive integers is twenty-two more than three times the sum of the integers:
10x = 3(x + (x+1) + (x+2)) + 22
10x = 3(3x + 3) + 22
10x = 9x + 9 + 22
10x - 9x = 31
x = 31 one is the smallest integer
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See if this checks out
10(31) = 3(31+32+33) + 22
310 = 3(96) + 22
310 = 288 + 22