SOLUTION: the smaller of two consecutive even integers is five more than one half of the greater x + x+2= 5 + 1/2 (2) hmmm, i don't think this is correct!

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: the smaller of two consecutive even integers is five more than one half of the greater x + x+2= 5 + 1/2 (2) hmmm, i don't think this is correct!      Log On


   

Question 102454This question is from textbook
: the smaller of two consecutive even integers is five more than one half of the greater
x + x+2= 5 + 1/2 (2)
hmmm, i don't think this is correct! This question is from textbook

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
if the consecutive even integers are:
2x+ and 2x%2B2
then:
2x+%2B+5+=+%281%2F2%29%2A%282x%2B2%29
2x+%2B+5+=+%28x%2B1%29+
2x+=+x+-4
2x+-x+=+-4+
x+=+-4
so
2x+=+-8 (this is smaller eveninteger)
and
%282x%2B2%29=+-6 (this is greater even integer)
since %281%2F2%29 of -6 is equal to -3
then -%283%2B5%29=-8